6.10.2013
3.15.2013
Death of Google Reader - Journey towards alternatives
Flashback
Long Long ago when INTERNET is booming up with so many websites its really hard to follow the interesting one. Its quite clumsy to go around miliions of sites to check for new posts.
No, you are not. RSS feed mechanism is the answer.
Just follow the RSS feed of your favourite site and the RSS reader will maintain the unread articles, favourite articles and so on. Voilla simple and effective solution to follow various sites.
Long Long ago when INTERNET is booming up with so many websites its really hard to follow the interesting one. Its quite clumsy to go around miliions of sites to check for new posts.
Am I Doomed ?
No, you are not. RSS feed mechanism is the answer.
Just follow the RSS feed of your favourite site and the RSS reader will maintain the unread articles, favourite articles and so on. Voilla simple and effective solution to follow various sites.
3.13.2013
Divide a number by 3 without using any arithmetic operators
How to divide a number by 3 without using operators + - / * %
NOTE: I am just trying to collect various answers down in this post available across multiple sites in internet as mentioned in references.
Solution 01:
NOTE: I am just trying to collect various answers down in this post available across multiple sites in internet as mentioned in references.
Solution 01:
#include <stdio.h> #include <stdlib.h> int main() { FILE *fp=fopen("temp.dat","w+b"); int number=12346; int divisor=3; char *buf = calloc(number,1); fwrite(buf,number,1,fp); rewind(fp); int result=fread(buf,divisor,number,fp); printf("%d / %d = %d", number, divisor, result); free(buf); fclose(fp); return 0; }
Checking Balance of Symbols in a expression
This article is part of article series - "Datastructures"
A balanced expression contains right number of closing and open braces.
For example:
Let us see how to find if an expression is balanced or not by checking for following operators [ ] { } and ( ) in the given expression.
A balanced expression contains right number of closing and open braces.
For example:
- [[ - unbalanced expression
- []{}() - balanced expression
- [(*)] - balanced expression
Let us see how to find if an expression is balanced or not by checking for following operators [ ] { } and ( ) in the given expression.
Using Stacks
2.05.2013
Conversion from Infix to Postfix
This article is part of article series - "Datastructures"
Converting a Fully Parenthesized Infix expression into Postfix expression
Analysis:
Five types of input characters- Opening parentheses
- Operands
- Operators
- Closing parentheses
- New line character (\n)
Pseudocode:
******************************************************** Function : main Calls : createStack freeStack pushIntoStack popFromStack Called by : NONE Input Parameters: Accepts input expression for processing Returns : Converts Fully paranthesized INFIX expression into POSTFIX expression ******************************************************** SET i to 0 GET infix expression from user into input_array SET var with input_array[i] CALL createStack WHILE var != end of string IF var equals to '(' THEN CALL pushIntoStack (stack, var) ELSE IF var is a number THEN PRINT var ELSE IF var is an arithmetic operator THEN CALL pushIntoStack (stack, var) ELSE IF var equals to ')' THEN WHILE stackTop != '(' IF stackTop is an arithmetic operator THEN PRINT stackTop popFromStack (stack) ENDIF ENDWHILE popFromStack (stack) ENDIF SET var with input_expression[INCREMENT i] ENDWHILE CALL freeStack (stack)
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