/* Ajith - Syntax Higlighter - End ----------------------------------------------- */

3.16.2013

Death of Google Reader - Journey towards alternatives

Flashback

Long Long ago when INTERNET is booming up with so many websites its really hard to follow the interesting one. Its quite clumsy to go around miliions of sites to check for new posts.

Am I Doomed ?

No, you are not. RSS feed mechanism is the answer.


Just follow the RSS feed of your favourite site and the RSS reader will maintain the unread articles, favourite articles and so on. Voilla simple and effective solution to follow various sites.

3.14.2013

Divide a number by 3 without using any arithmetic operators

How to divide a number by 3 without using operators + - / * %

NOTE: I am just trying to collect various answers down in this post available across multiple sites in internet as mentioned in references.

Solution 01:
#include <stdio.h>
#include <stdlib.h>

int main()
{
    FILE *fp=fopen("temp.dat","w+b");
    int number=12346;
    int divisor=3;
    char *buf = calloc(number,1);
    fwrite(buf,number,1,fp);
    rewind(fp);
    int result=fread(buf,divisor,number,fp);
    printf("%d / %d = %d", number, divisor, result);
    free(buf);
    fclose(fp);
    return 0;
}

3.13.2013

Checking Balance of Symbols in a expression

This article is part of article series - "Datastructures"

A balanced expression contains right number of closing and open braces.

For example:

  • [[ - unbalanced expression
  • []{}() - balanced expression
  • [(*)] - balanced expression

Let us see how to find if an expression is balanced or not by checking for following operators [ ] { } and ( ) in the given expression.

Using Stacks