/* Ajith - Syntax Higlighter - End ----------------------------------------------- */

11.14.2012

Finding Nth node from end of a Singly Linked List

This article is part of article series - "Datastructures"

Previous Article: Finding first node in a Loop in Singly Linked List.

Figure 1: Singly Linked List

Solution 01 - Brute Force Approach:
  1. Start at First Node of the List (call it curNodePtr).
  2. Assign curNodePtr to tmpPtr and count number of nodes after the curNodePtr.
  3. If number of nodes after curNodePtr are equal to N nodes or tmpPtr reaches END then break. If tmPtr reaches END but count not equal to N then return since we can't find the Nth node from the end of the Singly Linked List.
  4. Move the curNodePtr one step forward in the Linked List i.e curNodePtr now points to its next node in the list and start again from STEP-2.

11.07.2012

Reversing a Singly Linked List

This article is part of article series - "Datastructures"

Previous Article: Deleting a Node from a Singly Linked List.
Next Article: Detecting a Loop in Singly Linked List - Tortoise and Hare.

Let us see how to reverse a Singly Linked List.

Figure-1: Singly Linked List
Pseudocode:
cur_ptr = HEAD->NEXT
prev_ptr = NULL

forever:

   if cur_ptr == NULL
   break

   tmp_ptr  = prev_ptr
   prev_ptr = cur_ptr
   cur_ptr  = cur_ptr->NEXT
   
   prev_ptr->NEXT = tmp_ptr

HEAD->NEXT = prev_ptr
Complexity:
Time Complexity: O(n)
Space Complexity: O(3)

If we try on the example in Figure-1 we get the output as shown below

Figure-2: After reversing the Singly Linked List


Previous Article: Deleting a Node from a Singly Linked List.
Next Article: Detecting a Loop in Singly Linked List - Tortoise and Hare.